Problem of the Week 8

This is the 8th problem of the week of MTAP Reviewer.


The diagonal of a square is 6cm. Find the area of the square that is twice its size.


We can divide a square into several ways, one of which is using its diagonal.


Click on the image to enlarge

Now, using the diagonal of the square as side of the larger square, we can create a larger square as shown above. As seen, the diagonal of the square cuts the square into half. This half region makes a fourth of the larger square (Can you see why?).

Since the length of the side of the larger square is the diagonal of the smaller square 6, the area of the larger square is 6× 6 = 36.

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One Response to Problem of the Week 8

  1. G.C. says:

    if the G6 students had already had a background in pythagorean formula, they can just
    apply the concepts here.

    the diagonal of the square is 6.
    applying the formula, the side will be 3sqrt.of2 cm
    solving for the area of the given square, we have 18cm^2.
    since the larger square is twice its size, then 2(18cm^2) = 36cm^2.

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