This is the 2011 Math Challenge for Grade 6 questions 26-50. Questions 1-25 can be found here.
26.) A pyramid-like circus tent has a 32 m by 28 m rectangular base. If it is 15 m high, what volume of air does it enclose?
Answer:
Solution: v = (lwh)/3
v = (32 × 28 × 15)/3
v = (13440)/3
v = 4480 cu m.
27.) The parallel sides of a trapezoidal farm are 210 m by 150 m. If they are 120 m apart, what is the area of the farm in hectares?
Answer: 2.16 hectares
Solution: A = ((a+b))/2 h
A = ((210+150))/2 120
A = 360/2 (120)
A = 21600 sq m
Convert meter to hectares = 2.16 hectares
as a single logarithm with base 
.
if the point where 
attains its maximum, is also a zero of 
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in simplest terms?
, what is 
? 
, find 
.
?
in the equation 
.